ответ на задачу: Приготовили смесь из 9,6 г меди и 8 г оксида меди(II). Рассчитайте массовые доли каждого компонента. ω(Cu) = 9,6г/(9,6+8) * 100% = 54,5% ω(CuO) = 100% - 54,5% = 45,5% Ответ: ω(Cu) =54,5%, ω(CuO) =45,5%
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